Problems

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Let us introduce the notation – we denote the product of all natural numbers from 1 to \(n\) by \(n!\). For example, \(5!=1\times2\times3\times4\times5=120\).

a) Prove that the product of any three consecutive natural numbers is divisible by \(3!=6\).

b) What about the product of any four consecutive natural numbers? Is it always divisible by 4!=24?

Is it possible for \(n!\) to be written as \(2015000\dots 000\), where the number of 0’s at the end can be arbitrary?

The numbers \(1, 2, \dots , 9\) are divided into three groups. Prove that the product of the numbers in one of the groups will always be no less than 72.

The number of permutations of a set of \(n\) elements is denoted by \(P_n\).

Prove the equality \(P_n = n!\).

For any positive integer \(k\), the factorial \(k!\) is defined as a product of all integersbetween 1 and \(k\) inclusive: \(k! = k \times (k − 1) \times ... \times 1\). What’s the remainder when \(2025!+2024!+2023!+...+3!+2!+1!\) is divided by \(8\)?