Problems

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Found: 12

The Babylonian algorithm for deducing 2. The sequence of numbers {xn} is given by the following conditions: x1=1, xn+1=12(xn+2/xn) (n1).

Prove that limnxn=2.

What will the sequence from the previous problem 61297 be converging towards if we choose x1 as equal to 1 as the initial condition?

The iterative formula of Heron. Prove that the sequence of numbers {xn} given by the conditions x1=1, xn+1=12(xn+k/xn), converges. Find the limit of this sequence.

The algorithm of the approximate calculation of a3. The sequence {an} is defined by the following conditions: a0=a>0, an+1=1/3(2an+a/an2) (n0).

Prove that limnan=a3.

The sequence of numbers {an} is given by a1=1, an+1=3an/4+1/an (n1). Prove that:

a) the sequence {an} converges;

b) |a10002|<(3/4)1000.

The sequence of numbers {xn} is given by the following conditions: x1a, xn+1=a+xn. Prove that the sequence xn is monotonic and bounded. Find its limit.

We call the geometric-harmonic mean of numbers a and b the general limit of the sequences {an} and {bn} constructed according to the rule a0=a, b0=b, an+1=2anbnan+bn, bn+1=anbn (n0).

We denote it by ν(a,b). Prove that ν(a,b) is related to μ(a,b) (see problem number 61322) by ν(a,b)×μ(1/a,1/b)=1.

Problem number 61322 says that both of these sequences have the same limit.

This limit is called the arithmetic-geometric mean of the numbers a,b and is denoted by μ(a,b).

A regular dice is thrown many times. Find the mathematical expectation of the number of rolls made before the moment when the sum of all rolled points reaches 2010 (that is, it became no less than 2010).

A fair dice is thrown many times. It is known that at some point the total amount of points became equal to exactly 2010.

Find the mathematical expectation of the number of throws made to this point.