Problems

The digits of a 3 digit number $A$ were written in reverse order and this is the number $B$. Is it possible to find a value of $A$ such that the sum of $A$ and $B$ has only odd numbers as its digits?

Let $x$ be a 2 digit number. Let $A$, $B$ be the first (tens) and second (units) digits of $x$, respectively. Suppose $A$ is twice as large as $B$. If we add the square of $A$ to $x$ then we get the square of a certain whole number. Find the value of $x$.