Problems

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Found: 6

Prove that for any natural number a1>1 there exists an increasing sequence of natural numbers a1,a2,a3,, for which a12+a22++ak2 is divisible by a1+a2++ak for all k1.

The sequence of numbers {xn} is given by the following conditions: x1a, xn+1=a+xn. Prove that the sequence xn is monotonic and bounded. Find its limit.

We took several positive numbers and constructed the following sequence: a1 is the sum of the initial numbers, a2 is the sum of the squares of the original numbers, a3 is the sum of the cubes of the original numbers, and so on.

a) Could it happen that up to a5 the sequence decreases (a1>a2>a3>a4>a5), and starting with a5 – it increases (a5<a6<a7<)?

b) Could it be the other way around: before a5 the sequence increases, and starting with a5 – decreases?

a1,a2,a3, is an increasing sequence of natural numbers. It is known that aak=3k for any k. Find a) a100; b) a2022.