Is it possible to draw five lines from one point on a plane so that there are exactly four acute angles among the angles formed by them? Angles between not only neighboring rays, but between any two rays, can be considered.
Prove that no straight line can cross all three sides of a triangle, at points away from the vertices.
One of the four angles formed when two straight lines intersect is \(41^{\circ}\). What are the other three angles equal to?