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Anna has a garden shaped like an equilateral triangle of side \(8\) metres. She wants to plant \(17\) plants, but they need space – they need to be at least \(2\) metres apart in order for their roots to have access to all the microelements in the ground. Show that Anna’s garden is unfortunately too small.

A math circle student Emilio wrote a computer program for his house robot, Basil. Starting from 1, Basil should keep writing bigger and bigger numbers formed by 1s: 1, 11, 111, etc. The program terminates when Basil writes a number that is a multiple of 19. Prove that the program will terminate in fewer than 20 steps.

We know that the product \(c \times d\) is divisible by a prime \(p\). Show that either \(c\) or \(d\) must be divisible by \(p\).

Find a number which:

a) It is divisible by \(4\) and by \(6\), is has a total of 3 prime factors, which may be repeated.

b) It is divisible by \(6, 9\) and \(4\), but not divisible by \(27\). It has \(4\) prime factors in total, which may be repeated.

c) It is divisible by \(5\) and has exactly \(3\) positive divisors.

The number \(a\) has a prime factorization \(2^3 \times 3^2 \times 7^2 \times 11\). Is it divisible by \(54\)? Is it divisible by \(154\)?

a) The number \(a\) is even. Should \(3a\) definitely also be even?

b) The number \(5c\) is divisible by \(3\). Is it true that \(c\) is definitely divisible by \(3\)?

c) The product \(a \times b\) is divisible by \(7\). Is it true that one of these numbers is divisible by \(7\)?

d) The product \(c \times d\) is divisible by \(26\). Is it true that one of these numbers is divisible by \(26\)?

a) The number \(a^2\) is divisible by \(11\). Is \(a^2\) necessarily also divisible by \(121\)?

b) The number \(b^2\) is divisible by \(12\). Is \(b^2\) necessarily also divisible by \(144\)?

a) Prove that a number is divisible by \(8\) if and only if the number formed by its laast three digits is divisible by \(8\).

b) Can you find an analogous rule for \(16\)? What about \(32\)?

Look at this formula found by Euler: \(n^2 +n +41\). It has a remarkable property: for every integer number from \(1\) to \(21\) it always produces prime numbers. For example, for \(n=3\) it is \(53\), a prime. For \(n=20\) it is \(461\), also a prime, and for \(n=21\) it is \(503\), prime as well. Could it be that this formula produces a prime number for any natural \(n\)?