A graph is called Bipartite if it is possible to split all its vertices into two groups in such a way that there are no edges connecting vertices from the same group. Find out whic of the following graphs are bipartite and which are not:
Show that a bipartite graph with \(n\) vertices cannot have more than \(\frac{n^2}{4}\) edges.
In the numeral system with base \(k\) Alex is \(50\) years old. Next year he will be \(100\) years old in the numeral system with base \(k-1\). Find the age of Alex and value of \(k\) as decimal numbers.
In a graph \(G\), we call a matching any choice of edges in \(G\) in such a way that all vertices have only one edge among chosen connected to them. A perfect matching is a matching which is arranged on all vertices of the graph.
Let \(G\) be a graph with \(2n\) vertices and all the vertices have degree at least \(n\) (the number of edges exiting the vertex). Prove that one can choose a perfect matching in \(G\).
Imagine you are a manager of a very special hotel, a hotel with an infinite number of rooms, where each room has a natural number on the door \(1,2,3,4,...\). Only one guest can stay in each room and in most cases the hotel will be initially full with no vacant rooms left.
You will have to deal with unusual situations that may occur.
A new customer comes to the hotel and wants a room. It happened today that all the rooms are occupied. What should you do?
Now imagine you got \(10\) new guests arriving to the completely full hotel. What should you do now?
The next day you have even harder situation: to the hotel, where all the rooms are occupied arrives a bus with infinitely many new customers. In the bus all the seats have numbers \(1,2,3...\) corresponding to all natural numbers. How to deal with this one?
Imagine you have \(2\) new guests arriving to the full hotel. How do you accommodate them?
What would you do about \(10000\) new guests arriving to the full hotel?