Problems

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Found: 2291

The numbers \(a\) and \(b\) are integers and \(a>b\). Show that the gcd of \(a\) and \(b\) is equal to the gcd of \(b\) and \(a-b\).

A brave witch is out there hunting monsters for coins. She noticed that every 5th monster she encounters has wings, every 16th has a fiery breath, every 6th has fangs and every 14th has a pile of treasure. Now, the only monster with wings, fiery breath, fangs and a pile of treasure is a dragon and witches don’t hunt dragons. Suppose that the witch has just met a dragon and that every dragon has wings, firey breath, fangs and a pile of treasure. How many monsters will she have to hunt to meet another one?

Let \(a = 8 \times 9^2 \times 31^2 \times 7\) and \(b= 7^2 \times 2^3 \times 3^6 \times 23^2\). Find their greatest common divisor and least common multiple.

Let \(n\) be a nonnegative integer. What is the gcd of \(12n+9\) and \(9n+6\)?

The gcd of numbers \(a\) and \(b\) is \(72\). What can be their smallest possible product? What could be their greatest possible product?

a) Two numbers, \(a\) and \(b\), are relatively prime and their product is equal to \(60\). What could these numbers be? Find all the possibilities.
b) The GCD of two numbers, \(c\) and \(d\), is \(18\) and their product is \(2^4 \times 3^5 \times 7\). What could these numbers be? Find all the answers.

a) Can you measure \(5\) litres of milk using two buckets of volumes \(4\) and \(11\) litres respectively?
b) Can you measure \(7\) litres of milk using buckets of volumes \(8\) and \(12\) litres respectively?

a) A mighty dragon has several rubies in his treasure. He is able to divide the rubies into groups of \(3\), \(5\) or \(11\). How many rubies does he have, if we know that is fewer than \(200\)?
b) The same dragon also has some emeralds. He is \(6\) emeralds short to be able to divide them into groups of \(13\), one emerald short to be able to divide them into groups of \(5\), but if he wants to divide them into groups of \(8\), he is left with one emerald. How many emeralds does he have if we know it is fewer than \(500\)?

Let \(n\) be a natural number. Show that the fraction \(\frac{21n+4}{14n+3}\) is irreducible, i.e. it cannot be simplified.

Let \(m\) and \(n\) be two positive integers with \(m<n\) such that \[\gcd(m,n)+ \text{lcm}(m,n)=m+n.\] Show that \(m\) divides \(n\).