Problem #WSP-000381

Problem

Show that if $1 + 3 + 5 + 7 + . . . + 97 + 99 = 50^{2}$ , then $1 + 3 + 5 + 7 + . . . + 97 + 99 + 101 = 51^{2}$ . Don’t forget that $(a + b)^{2} = a^{2} + 2 a b + b^{2}$ .

To see the solution register and get verified.