Problems

Age
Difficulty
Found: 578

Illustrate with a picture

(a) \((a-b)^2 = a^2 - 2ab + b^2\),

(b) \(a^2 - b^2 = (a-b)(a+b)\),

(c) \((a+b+c)^2 = a^2 + b^2 + c^2 + 2ab + 2ac + 2bc\).

Suppose \(a>b\). Explain using the number line why

(a) \(a-c>b-c\), (b) \(2a>2b\).

Suppose \(a>b\) and \(c>d\). Prove that \(a+c>b+d\).

Using mathematical induction prove that \(2^n \geq n + 1\) for all natural numbers.

Circles and lines are drawn on the plane. They divide the plane into non-intersecting regions, see the picture below.

Show that it is possible to colour the regions with two colours in such a way that no two regions sharing some length of border are the same colour.

Consider a number consisting of \(3^n\) digits, all ones, such as 111 or 111111111 for example. Show that such a number with \(3^n\) digits is divisible by \(3^n\).

Numbers \(1,2,\dots,n\) are written on a whiteboard. In one go Louise is allowed to wipe out any two numbers \(a\) and \(b\), and write their sum \(a+b\) instead. Louise enjoys erasing the numbers, and continues the procedure until only one number is left on the whiteboard. What number is it? What if instead of \(a+b\) she writes \(a+b-1\)?

Prove that

(a) \[1^2 + 2^2 + 3^2 + \dots + n^2 = \frac{1}{6} n (n+1)(2n+1)\]

(b) \[1^2 + 3^2 + 5^2 + \dots + (2n-1)^2 = \frac{1}{3} n (2n-1)(2n+1)\].

Is “If you come here, then you are mad” the same thing as “If you are not mad, then you wouldn’t have come here”.

Is “if \(x = y\) then \(x^2= y^2\)” the same thing as “if \(x^2 \neq y^2\) then \(x \neq y\)”?